A) P.E. increases and K.E. decreases
B) P.E. decreases and K.E. increases
C) Both kinetic energy and potential energy increase
D) Both K.E. and P.E. decrease
Correct Answer: A
Solution :
P.E.\[\propto -\frac{1}{r}\] and K.E.\[\propto \frac{1}{r}\] As r increases so K.E. decreases but P.E. increases.You need to login to perform this action.
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