A) R
B) 3R
C) \[\frac{5R}{36}\]
D) \[\frac{8R}{9}\]
Correct Answer: C
Solution :
Wave number \[=\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For first Balmer line n1= 2, n2=3 \[\therefore \]Wave number \[=R\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)=R\left( \frac{9-4}{9\times 4} \right)=\frac{5R}{36}\]
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