A) v
B) \[\frac{22}{5}v\]
C) \[\frac{5}{2}v\]
D) \[\frac{2}{5}v\]
Correct Answer: D
Solution :
vn \[\propto \frac{1}{n}\] Þ \[\frac{{{v}_{5}}}{{{v}_{2}}}=\frac{2}{5}\Rightarrow {{v}_{5}}=\frac{2}{5}{{v}_{2}}=\frac{2}{5}v\]
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