A) \[H{{e}^{+}}\]
B) \[L{{i}^{++}}\]
C) \[N{{e}^{9+}}\]
D) \[N{{a}^{10+}}\]
Correct Answer: A
Solution :
\[\bar{\nu }\propto \frac{1}{\lambda }\propto {{Z}^{2}}\Rightarrow \lambda {{Z}^{2}}=\]constant \[\Rightarrow \lambda =\frac{\lambda }{4}{{Z}^{2}}\Rightarrow Z=2\]
You need to login to perform this action.
You will be redirected in
3 sec
