A) One
B) Two
C) Three
D) Four
Correct Answer: C
Solution :
Final energy of electron \[=-13.6+12.1=-1.51\,eV.\] which is corresponds to third level i.e. \[n=3\]. Hence number of spectral lines emitted \[=\frac{n(n-1)}{2}=\frac{3(3-1)}{2}=3\]You need to login to perform this action.
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