A) \[\frac{{{e}^{2}}}{{{r}^{2}}}\]
B) \[\frac{{{e}^{2}}}{2r}\]
C) \[\frac{{{e}^{2}}}{r}\]
D) \[\frac{{{e}^{2}}}{2{{r}^{2}}}\]
Correct Answer: B
Solution :
Potential energy of electron in nth orbit of radius r in H-atom \[U=-\frac{{{e}^{2}}}{r}\] (in CGS) ∵ K.E.\[=\frac{1}{2}|P.E.|\] Þ \[K=\frac{{{e}^{2}}}{2r}\]You need to login to perform this action.
You will be redirected in
3 sec