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JEE Main & Advanced Physics Atomic Physics Question Bank Atomic Structure

  • question_answer
    The energy of a hydrogen atom in its ground state is \[-13.6\ eV\]. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is                  [CBSE PMT 1996; CBSE PMT 1997, 2001; MP PET 2000; AFMC 2000, 01, 02; BCECE 2003]

    A)            ? 2.72 eV                                

    B)            ? 0.85 eV

    C)            ? 0.54 eV                                

    D)            ? 3.4 eV

    Correct Answer: D

    Solution :

               \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}=\frac{-13.6}{4}=-3.4eV\]


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