A) 1215.4 Å
B) 2500 Å
C) 7500 Å
D) 600 Å
Correct Answer: A
Solution :
\[\frac{1}{{{\lambda }_{Balmer}}}=R\left[ \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right]=\frac{5R}{36}\], \[\frac{1}{{{\lambda }_{Lyman}}}=R\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right]=\frac{3R}{4}\] \[\therefore {{\lambda }_{Lyman}}={{\lambda }_{Balmer}}\times \frac{5}{27}=1215.4\ {\AA}\]
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