A) \[13.4\,\,g\]
B) \[1.34\,\,g\]
C) \[134\,\,g\]
D) \[0.134\,\,g\]
Correct Answer: A
Solution :
\[1\] mole of sodium oxalate\[=134\,\,g\] Weight of \[0.1\] mole of\[N{{a}_{2}}{{C}_{2}}{{O}_{4}}\]\[=0.1\times 134=13.4\,\,g\]You need to login to perform this action.
You will be redirected in
3 sec