[Atomic mass of Na = 23 u, Br = 80 u] |
A) 40 g
B) 46 g
C) 52 g
D) 23 g
Correct Answer: B
Solution :
Electrolysis decomposes ionic compounds into their elements. Mass of NaBr = 23 + 80 = 103 u Now, 103 g of NaBr contains 23 g of Na \[\therefore \] 206 g of NaBr will contain \[\frac{23}{103}\times 206=46\text{ g of Na}\]You need to login to perform this action.
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