A)
Fe S 0 2 3 12
B)
Fe S 0 1 1 4
C)
Fe S 0 0.2 0.3 1.2
D)
Fe S 0 0.1 0.1 0.4
Correct Answer: C
Solution :
The molar mass of \[\text{F}{{\text{e}}_{\text{2}}}{{\text{(S}{{\text{o}}_{\text{4}}}\text{)}}_{\text{3}}}\text{=400g}\] \[\text{No}\text{. of mole=}\frac{\text{given mass}}{\text{molar mass}}=\frac{40}{400}=0.1\] 1 mol of ferric sulphate contains 2 mol of iron. \[\therefore \] 0.1 mol of ferric sulphate will contain \[2\times 0.1\] = 0.2 mol of Fe 1 mol of ferric sulphate contains 3 mol of S. \[\therefore \] 0.1 mol of ferric sulphate will contain \[\text{3}\times \text{0}\text{.1=0}\text{.3 mol of S}\] 1 mol of ferric sulphate contains 12 mol of oxygen. \[\therefore \] 0.1 mol of ferric sulphate will contain \[=12\times 0.1\] =1.2 mol of oxygen
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