A) \[2\]moles
B) \[3\]moles
C) \[1\]mole
D) \[4\]moles
Correct Answer: D
Solution :
Formula weight of\[CaC{{O}_{3}}\]. \[=40+12+3\times 16=100\,\,a.m.u\] Therefore, \[1\]mole of\[CaC{{O}_{3}}=100\,\,g\] So, \[400\,\,g\] is equal to \[4\]mole\[CaC{{O}_{3}}=100\,\,g\]You need to login to perform this action.
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