A) \[2.4\times {{10}^{-23}}\]atoms
B) \[2.4\times {{10}^{-23}}\]atoms
C) \[1.2\times {{10}^{23}}\]atoms
D) \[1.2\times {{10}^{-23}}\]atoms
Correct Answer: C
Solution :
Atomic weight of\[S=32.06\,\,a.m.u\]\[1\]gram atomic weight of \[S=32.06\,\,g=\]\[6.023\times {{10}^{23}}\]atoms of sulphur. Number of atoms in\[6.4\,\,g\]of\[S\]\[=\frac{6.4}{32.06}\times 6.023\times {{10}^{23}}=1.2\times {{10}^{23}}\]atomsYou need to login to perform this action.
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