Answer:
(i) The negative sign indicates that the electron is bound to the nucleus by electrostatic forces of attraction. (ii) Energy in ground state, \[{{E}_{1}}=-13.6eV\] Energy in first excited state, \[{{E}_{2}}=-\frac{13.6}{{{2}^{2}}}=-3.4eV\] Required energy, \[\Delta E={{E}_{2}}-{{E}_{1}}\] \[=-3.4+13.6=\mathbf{10}\mathbf{.2eV}.\]
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