Answer:
The ratio of the radius of electron's orbit to the radius of nucleus is\[{{10}^{-10}}m/{{10}^{-15}}m\])\[=\text{ 1}{{0}^{\text{5}}}\]. That is the radius of the electron's orbit is \[\text{1}{{0}^{\text{5}}}\] times larger than the radius of nucleus. If the radius of the earth's orbit around the sun were \[\text{1}{{0}^{\text{5}}}\] times larger than the radius of the sun, the radius of the earth's orbit would be\[\text{1}{{0}^{\text{5}}}\times \text{ 7 }\times \text{ 1}{{0}^{\text{8}}}\text{m }=\text{ 7 }\times \text{ 1}{{0}^{\text{13}}}\text{m}\text{.}\] This is more than \[\text{1}00\] times greater than the actual orbital radius. Thus the earth would be much farther away from the sun. It implies that an atom contains a much greater fraction of empty space than our solar system does.
You need to login to perform this action.
You will be redirected in
3 sec