A) \[60{}^\circ \]
B) \[{{\cot }^{-1}}2.23\]
C) \[{{\cot }^{-1}}1.232\]
D) \[30{}^\circ \]
Correct Answer: C
Solution :
\[l=280\,cm,\,b=140\,cm,\,\phi =30{}^\circ \] \[\cot \,\phi -\cot \,\theta =\frac{b}{l}\] \[\cot \,30{}^\circ -\cot \,\theta =\frac{140}{280}=0.5\] \[\sqrt{3}-\cot \theta =0.5\] \[\theta =\cot {{\theta }^{-1}}(1.232)\]
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