• # question_answer A motor car has wheel base of 280 cm and the pivot distance of front stub axles is 140 cm. When the outer wheel has turned through 30, the angle of turn of the inner front wheel for correct steering will be: A) $60{}^\circ$                          B) ${{\cot }^{-1}}2.23$C) ${{\cot }^{-1}}1.232$            D) $30{}^\circ$

$l=280\,cm,\,b=140\,cm,\,\phi =30{}^\circ$ $\cot \,\phi -\cot \,\theta =\frac{b}{l}$ $\cot \,30{}^\circ -\cot \,\theta =\frac{140}{280}=0.5$ $\sqrt{3}-\cot \theta =0.5$ $\theta =\cot {{\theta }^{-1}}(1.232)$