• # question_answer In flat belt drive, if the slip between the driver and the belt is 1%, that between belt and follower is 3% and driver and follower pulley diameters are equal, then the velocity ratio of the drive will be: A) 0.99                             B) 0.98C) 0 0.97              D) 0.96

Total slip, $s={{s}_{1}}+{{s}_{2}}=1+3=4%$ $\frac{{{N}_{2}}}{{{N}_{1}}}=1=s=1-0.04=0.96$