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Automobile Engineering
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In flat belt drive, if the slip between the driver and the belt is 1%, that between belt and follower is 3% and driver and follower pulley diameters are equal, then the velocity ratio of the drive will be:
A)0.99
B)0.98
C)0 0.97
D)0.96
Correct Answer:
D
Solution :
Total slip, \[s={{s}_{1}}+{{s}_{2}}=1+3=4%\] \[\frac{{{N}_{2}}}{{{N}_{1}}}=1=s=1-0.04=0.96\]