A) 17
B) 18
C) 19
D) 20
Correct Answer: B
Solution :
[b] \[\frac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}}{4}=16\] \[\Rightarrow \] \[({{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}})=60\] \[\frac{1}{2}({{x}_{2}}+{{x}_{3}}+{{x}_{4}})=23\] \[\Rightarrow \] \[({{x}_{2}}+{{x}_{3}}+{{x}_{4}})=46\] \[\therefore \] \[{{x}_{1}}=(64-46)=18\] |
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