A) 16
B) 46
C) 20
D) 18
Correct Answer: B
Solution :
[b] Let first, second, third and fourth numbers be a, b, c and d, respectively. Then, \[\frac{a+b+c}{3}=2d\] Now, \[\frac{a+b+c+d}{4}=12\] \[\Rightarrow \] \[\frac{6d+d}{4}=12\]\[\Rightarrow \]\[d=\frac{48}{7}\] |
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