A) increased by 2
B) increased by 1
C) remain the same
D) increased by 1.4
Correct Answer: B
Solution :
[b] Let the 5 consecutive natural numbers be \[x,\] \[x+1,\]\[x+2,\]\[x+3\]and \[x+4.\] Then, \[x+(x+1)+(x+2)+\text{(}x+3)+(x+4)=5n\] \[\Rightarrow \] \[5x+10=5n\] \[\Rightarrow \] \[x=\frac{5\,(n-2)}{5}=(n-2)\] \[\therefore \] 7 consecutive natural numbers are \[(n-2),\]\[(n-1),\]\[n,\]\[(n+1),\]\[=2884\]\[(n+3),\]\[(n+4)\] Their average \[=\frac{7n+7}{7}=\frac{7(n+1)}{7}=(n+1)\] So, the average increases by 1. |
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