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SSC Quantitative Aptitude Average Question Bank Average (II)

  • question_answer
    If the average of m numbers is \[{{n}^{2}}\] and that of n numbers is \[{{m}^{2}},\] then the average of \[(m+n)\] numbers is

    A) \[(m-n)\]

    B) \[mn\]

    C) \[(m+n)\]

    D) \[m/n\]

    Correct Answer: B

    Solution :

    [b] Total of \[(m+n)\]numbers\[=(m{{n}^{2}}+n{{m}^{2}})=mn\,(m+n)\] Average of \[(m+n)\] numbers \[=\frac{mn\,(m+n)}{(m+n)}=mn\]


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