A) 15.2 yr
B) 16 yr
C) 16.2 yr
D) 16.4 yr
Correct Answer: B
Solution :
[b] Sum of ages of 40 students \[=(15\times 40)yr=600yr\] Average of \[(40+10)\] students \[=15.2\,\,yr\] Sum of ages of 50 students \[=(15.2\times 50)yr760yr\] Sum of ages of 10 new students \[=(760-600)yr=160yr\] Required average \[=\frac{160}{10}yr=16yr\] |
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