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SSC Quantitative Aptitude Average Question Bank Average (II)

  • question_answer
    10 yr ago, the average age of a family of 4 members was 24 yr. Two children having been born, the average age of the family is same today. What is the present age of the youngest child, if they differ in age by 2 yr?

    A) 1 yr

    B) 2yr

    C) 3 yr

    D) 5yr

    Correct Answer: C

    Solution :

    [c] Let the age of youngest child be x yr. Then, age of the other child \[=(x+2)\,yr\] Average age of 6 members today = 24 yr Sum of the ages of 6 members today \[=(24\times 6)\,yr=144\,yr\] \[(24\times 4)+(10\times 4)+x+(x+2)=144\] \[\Rightarrow \]   \[2x=6\] \[\Rightarrow \]   \[x=3\] Present age of youngest child = 3 yr


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