A) \[(A-1)\]
B) \[(A-3)\]
C) \[(A+1)\]
D) \[(A+3)\]
Correct Answer: B
Solution :
[b] Let there be 3m boys and m girls. Total score \[=4mA.\] Total score of boys \[=3m\,\,(A+1)=3mA+3m\] Total score of girls \[=4mA-(3mA+3m)=(mA-3m)\] Average score of girls \[=\frac{(mA-3m)}{m}=\frac{m\,(A-3)}{m}=(A-3)\] |
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