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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Basic Terms

  • question_answer
    The number of ions formed when cuprammonium sulphate is dissolved in water is [KCET 1993]

    A) 1

    B) 2

    C) 4

    D) Zero

    Correct Answer: B

    Solution :

      Cuprammonium salt-\[[Cu\,{{(N{{H}_{3}})}_{4}}]\,S{{O}_{4}}\] \[[Cu\,{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}\]⇌\[{{[Cu\,{{(N{{H}_{3}})}_{4}}]}^{2+}}+SO_{4}^{2-}\] So, it will give two ions in water.


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