A) Ferricyanide
B) Ferrous ferricyanide
C) Ferrous cyanide
D) Ferriferrocyanide
Correct Answer: B
Solution :
Turnbull?s blue is \[K\{F{{e}^{\text{II}}}[F{{e}^{\text{III}}}{{(CN)}_{6}}]\}\].You need to login to perform this action.
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