A) 819 K
B) 819°C
C) 600°C
D) 600 K
Correct Answer: B
Solution :
\[v\propto \sqrt{T}\]Þ \[\frac{{{v}_{2}}}{{{v}_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}\]Þ\[2=\sqrt{\frac{{{T}_{2}}}{(273+0)}}\] \[\Rightarrow \] \[{{T}_{2}}=273\times 4=1092\,K={{819}^{o}}C\]You need to login to perform this action.
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