A) His watch is set 3 sec. faster
B) His watch is set 3 sec. slower
C) His watch is set correctly
D) None of the above
Correct Answer: B
Solution :
\[\text{Time}=\frac{\text{Distance }}{\text{Velocity}}=\frac{1000}{330}=3.03\]\[\sec \]. Sound will be heard after 3.03 sec. So his watch is set 3sec, slower.You need to login to perform this action.
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