A) 340 m
B) 1620 m
C) 680 m
D) 1700 m
Correct Answer: A
Solution :
Total time taken for both the echoes \[t={{t}_{1}}+{{t}_{2}}=2\]sec but \[t=\frac{2{{d}_{1}}}{v}+\frac{2{{d}_{2}}}{v}\]\[\Rightarrow t=\frac{2}{v}\left( {{d}_{1}}+{{d}_{2}} \right)\] \[\Rightarrow ({{d}_{1}}+{{d}_{2}})=\frac{v\times t}{2}=\frac{340\times 2}{2}\]=340m.You need to login to perform this action.
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