JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    A man stands in front of a hillock and fires a gun. He hears an echo after 1.5 sec. The distance of the hillock from the man is (velocity of sound in air is 330 m/s) [EAMCET (Eng.) 1998; CPMT 2000]

    A)            220 m                                      

    B)            247.5 m

    C)            268.5 m                                  

    D)            292.5 m

    Correct Answer: B

    Solution :

                If d is the distance between man and reflecting surface of sound then for hearing echo                    \[2d=v\times t\Rightarrow d=\frac{330\times 1.5}{2}=247.5\]\[m\]


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