JEE Main & Advanced Physics Wave Mechanics Question Bank Beats

  • question_answer
    Two waves \[y=0.25\sin 316\,t\] and \[y=0.25\sin 310\,t\] are travelling in same direction. The number of beats produced per second will be [CPMT 1993; JIPMER 2000]

    A)            6    

    B)            3

    C)            3/p

    D)            3p

    Correct Answer: C

    Solution :

               \[{{n}_{1}}=\frac{316}{2\pi }\] and \[{{f}_{2}}=\frac{310}{2\pi }\] Number of beats heard per second = n1 ? n2 =\[\frac{316}{2\pi }-\frac{310}{2\pi }=\frac{3}{\pi }\]


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