A) 256 + 5 Hz
B) 256 + 2Hz
C) 256 ? 2 Hz
D) 256 ? 5Hz
Correct Answer: D
Solution :
Suppose \[{{n}_{P}}=\] frequency of piano =? \[({{n}_{P}}\propto \sqrt{T})\] \[{{n}_{f}}=\] Frequency of tuning fork \[=256Hz\] x = Beat frequency = 5 bps, which is decreasing (5®2) after clanging the tension of piano wire Also, tension of piano wire is increasing so \[{{n}_{P}}\downarrow \] Hence nP? nf = x¯ Wrong nf ? nP= x¯ Correct Þ nP = nf ? x = 256 ? 5 Hz.You need to login to perform this action.
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