A) \[\frac{1}{30}\]
B) \[\frac{1}{10}\]
C) \[\frac{1}{3}\]
D) \[\frac{1}{15}\]
Correct Answer: A
Solution :
\[\sum\limits_{k=0}^{4}{P(X=k)}=1\Rightarrow \sum\limits_{k=0}^{4}{C{{k}^{2}}}=1\] \[\Rightarrow C({{1}^{2}}+{{2}^{2}}+{{3}^{2}}+{{4}^{2}})=1\Rightarrow C=\frac{1}{30}\].
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