A) \[\frac{5}{16}\]
B) \[\frac{1}{2}\]
C) \[\frac{3}{16}\]
D) \[\frac{3}{2}\]
Correct Answer: A
Solution :
By Binomial theorem, \[P={}^{5}{{C}_{3}}\times {{\left( \frac{1}{2} \right)}^{3}}{{\left( \frac{1}{2} \right)}^{2}}\Rightarrow P=\frac{5}{16}.\]
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