A) \[\frac{11}{36}\]
B) \[\frac{7}{12}\]
C) \[\frac{35}{36}\]
D) None of these
Correct Answer: A
Solution :
Probability of occurrence of ?4?\[=\frac{1}{6}\] Probability of inoccurrence of '4' \[=\frac{5}{6}\] \[\therefore \]Required probability \[={{\,}^{2}}{{C}_{1}}\left( \frac{1}{6} \right)\,\left( \frac{5}{6} \right)\,+{{\,}^{2}}{{C}_{2}}{{\left( \frac{1}{6} \right)}^{2}}{{\left( \frac{5}{6} \right)}^{0}}=\frac{11}{36}\].
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