A) \[\frac{1}{2}\]
B) \[\frac{3}{4}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{4}\]
Correct Answer: D
Solution :
Probability of getting odd number \[=\frac{3}{6}=\frac{1}{2}\] Hence required probability \[={}^{2}{{C}_{2}}{{\left( \frac{1}{2} \right)}^{2}}{{\left( \frac{1}{2} \right)}^{0}}=\frac{1}{4}.\]
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