A) \[\frac{125}{216}\]
B) \[\frac{215}{216}\]
C) \[\frac{1}{216}\]
D) \[\frac{91}{216}\]
Correct Answer: D
Solution :
Required probability \[={}^{3}{{C}_{1}}\left( \frac{1}{6} \right)\text{ }{{\left( \frac{5}{6} \right)}^{2}}+{}^{3}{{C}_{2}}{{\left( \frac{1}{6} \right)}^{2}}\left( \frac{5}{6} \right)+{}^{3}{{C}_{3}}{{\left( \frac{1}{6} \right)}^{3}}{{\left( \frac{5}{6} \right)}^{0}}=\frac{91}{216}.\]
You need to login to perform this action.
You will be redirected in
3 sec
