A) \[\frac{1}{1296}\]
B) \[\frac{4}{6}\]
C) 1
D) \[\frac{1295}{1296}\]
Correct Answer: A
Solution :
Probability of coming ?six? in one throw is \[\frac{1}{6}\] Hence required probability is given by \[={}^{4}{{C}_{4}}{{\left( \frac{1}{6} \right)}^{4}}.{{\left( \frac{5}{6} \right)}^{0}}=\frac{1}{1296}.\]
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