A) \[-\frac{3}{4}{{x}^{4}}\]
B) \[\frac{{{x}^{3}}}{2}\]
C) \[-\frac{{{x}^{3}}}{2}\]
D) \[\frac{3}{4}{{x}^{4}}\]
Correct Answer: B
Solution :
Expansion of \[{{(1-2x)}^{3/2}}\] \[=1+\frac{3}{2}(-2x)+\frac{3}{2}.\frac{1}{2}.\frac{1}{2}{{(-2x)}^{2}}+\frac{3}{2}.\frac{1}{2}\left( -\frac{1}{2} \right)\frac{1}{6}{{(-2x)}^{3}}+.....\] Hence \[{{4}^{th}}\]term is \[\frac{{{x}^{3}}}{2}\]
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