A) 5
B) 6
C) 4
D) 7
Correct Answer: A
Solution :
We have, \[{{T}_{r+1}}=\frac{\frac{7}{2}\left( \frac{7}{2}-1 \right)\,\,\left( \frac{7}{2}-2 \right)...\left( \frac{7}{2}-r+1 \right){{x}^{r}}}{r!}\] This will be the first negative term when \[\frac{7}{2}-r+1<0\]i.e. \[r>\frac{9}{2}\] Hence r = 5.You need to login to perform this action.
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