A) n
B) \[n+1\]
C) 1
D) - 1
Correct Answer: C
Solution :
Since \[1+2x+3{{x}^{2}}+4{{x}^{3}}+....\infty ={{(1-x)}^{-2}}\] Therefore, we have \[{{(1+2x+3{{x}^{2}}+4{{x}^{3}}+....\infty )}^{1/2}}={{\{{{(1-x)}^{-2}}\}}^{1/2}}\] \[={{(1-x)}^{-1}}=1+x+{{x}^{2}}+....+{{x}^{n}}+....\infty \] \ The coefficient of \[{{x}^{n}}=1\].You need to login to perform this action.
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