A) 100
B) 200
C) 300
D) 400
Correct Answer: D
Solution :
\[B=\frac{{{\mu }_{0}}{{\mu }_{r}}Ni}{2\pi r}\Rightarrow 1=\frac{4\pi \times {{10}^{-7}}\times {{\mu }_{r}}\times 400\times 2}{0.4}\Rightarrow {{\mu }_{r}}=400\]
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