A) 1: \[\sqrt{2}\]
B) 1 : 2
C) 2 : 1
D) \[\sqrt{3}\,\,:\,\,1\]
Correct Answer: A
Solution :
\[{{B}_{1}}={{B}_{2}}=B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2\pi i}{r}\] \[{{B}_{net}}=\sqrt{2}B\] \[\Rightarrow \frac{B}{{{B}_{net}}}=\frac{1}{\sqrt{2}}\]You need to login to perform this action.
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