A) \[\frac{{{\mu }_{o}}i}{4r}\]
B) \[\frac{{{\mu }_{o}}i}{2r}\]
C) \[\frac{{{\mu }_{o}}i}{2\pi r}(\pi +1)\]
D) \[\frac{{{\mu }_{o}}i}{2\pi r}(\pi -1)\]
Correct Answer: C
Solution :
The given circuit can be considered as follows \[{{B}_{\text{loop}}}=\frac{{{\mu }_{0}}i}{2r}\]¤ \[{{B}_{\text{conductor}}}=\frac{{{\mu }_{0}}i}{2\pi r}\]¤ \[{{B}_{\text{net}}}=\frac{{{\mu }_{0}}i}{2\pi r}(\pi +1)\]¤You need to login to perform this action.
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