A) \[5\times {{10}^{-5}}\]
B) \[7\times {{10}^{-5}}\]
C) \[12\times {{10}^{-5}}\]
D) \[{{10}^{-5}}\]
Correct Answer: A
Solution :
\[{{B}_{net}}=\sqrt{B_{1}^{2}+B_{2}^{2}}\] \[=\frac{{{\mu }_{0}}}{4\pi }.\frac{2\pi }{r}\sqrt{i_{1}^{2}+i_{2}^{2}}\] \[={{10}^{-7}}\times \frac{2\pi }{2\pi \times {{10}^{-2}}}\sqrt{{{(3)}^{2}}+{{(4)}^{2}}}=5\times {{10}^{-5}}\,wb/{{m}^{2}}\]
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