JEE Main & Advanced Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव Question Bank Biot-savart's Law and Amperes Law

  • question_answer
    A particle carrying a charge equal to 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 metre. The value of the magnetic field produced at the centre will be \[({{\mu }_{0}}=\] permeability for vacuum) [CPMT 1986; KCET 2001; BHU 2001]

    A)            \[\frac{{{10}^{-7}}}{{{\mu }_{0}}}\]                                

    B)            \[{{10}^{-17}}{{\mu }_{0}}\]

    C)            \[{{10}^{-6}}{{\mu }_{0}}\]    

    D)            \[{{10}^{-7}}{{\mu }_{0}}\]

    Correct Answer: B

    Solution :

                       \[i=\frac{q}{t}=100\times e\] \[{{B}_{\text{centre}}}=\frac{{{\mu }_{o}}}{4\pi }.\frac{2\pi i}{r}=\frac{{{\mu }_{o}}}{4\pi }.\frac{2\pi \times 100e}{r}\] \[=\frac{{{\mu }_{o}}\times 200\times 1.6\times {{10}^{-19}}}{4\times 0.8}={{10}^{-17}}{{\mu }_{o}}\]


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