A) \[0.125\,wb/{{m}^{2}}\]
B) \[1.25\,wb/{{m}^{2}}\]
C) \[12.5\,wb/{{m}^{2}}\]
D) \[125\,wb/{{m}^{2}}\]
Correct Answer: C
Solution :
\[B=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2\pi (q\nu )}{r}\] \[={{10}^{-7}}\times \frac{2\times 3.14\times (1.6\times {{10}^{-19}}\times 6.6\times {{10}^{15}})}{0.53\times {{10}^{-10}}}\]\[=12.5\,Wb/{{m}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
