A) 5000
B) 100
C) 50
D) 25
Correct Answer: C
Solution :
\[B=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2\pi Ni}{r}\] Þ \[3.14\times {{10}^{-3}}=\frac{{{10}^{-7}}\times 2\times 3.14\times N\times 10}{(10\times {{10}^{-2}})}\] Þ \[N=50\]
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